I am trying to find the general solution of
dy/dx=y^2(1-y)
So far I have rearranged to get 1/dx=y^2(1-y).dy
And have managed to integrate the RHS but, how would I go about integrating the 1/dx part?
First, move the dx to the other side:
$\displaystyle dy = y^2 (1 - y) dx $.
Then put all the y's on the side with the dy:
$\displaystyle \frac{dy}{y^2(1-y)} = dx $.
Now you can integrate both sides. The LHS can be integrated after a partial fraction decomposition.