1. ## Integration

I am trying to find the general solution of

dy/dx=y^2(1-y)

So far I have rearranged to get 1/dx=y^2(1-y).dy

And have managed to integrate the RHS but, how would I go about integrating the 1/dx part?

2. First, move the dx to the other side:
$dy = y^2 (1 - y) dx$.

Then put all the y's on the side with the dy:
$\frac{dy}{y^2(1-y)} = dx$.

Now you can integrate both sides. The LHS can be integrated after a partial fraction decomposition.