If g(s,t)=f( s2-t2 , t2-s2 ) show that t(dg/ds)+s(dg/dt)=0
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Before I can help, i just have to clarify some notation. Do we define $\displaystyle g(s,t) = f(2s - 2t, 2t-2s)$ or $\displaystyle g(s,t) = f(s_{2} - t_{2}, t_{2}-s_{2})$?
oh! Sorry :S It is actually $\displaystyle g(s,t) = f(s^{2} - t^{2}, t^{2}-s^{2}) $
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