Hello!

I'm having some problems with Calculus. I can't even figure out how to get started, let alone do the problem :S

2)Calculate area enclosed by y^2 = 2x+6 and y = x -1

3) Calculate the integral

Thanks guys ;)

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- December 2nd 2009, 02:42 AMfunnytimIntegrals
Hello!

I'm having some problems with Calculus. I can't even figure out how to get started, let alone do the problem :S

2)Calculate area enclosed by y^2 = 2x+6 and y = x -1

3) Calculate the integral

Thanks guys ;) - December 2nd 2009, 02:52 AMtonio

I'll give you a hand with the first one, you try to make some work of your own with the other ones:

Put As the function in the integral is continuous and defined everywhere, the Fundamental Theorem of integral Calculus tells us that

, where is a primitive function of the integrand function, but then:

Tonio - December 2nd 2009, 02:56 AMsimplependulum
For question three .

Consider

Then make a suitable substitution (Happy) - December 2nd 2009, 03:05 AMCalculus26
1.For your first question see attachment

2. For your second question see second attachment

3.For your third question write sin(2x) = 2sin(x)cos(x)

Then make the substitution u = cos(x) you will obtain -2u/(1+u^2)

in the integrand which you should be able to do - December 3rd 2009, 02:31 AMfunnytim
Thanks guys, you're great!

One question in#2 though. After i obtain:

http://www.imagechicken.com/uploads/...6085495900.jpg

How do I calculate it to obtain the answer, 18?

Thank you again! - December 3rd 2009, 02:58 AMCalculus26
Integrate and evaluate at the limits---submit your work if you don't get 18 and I'll see what happened

- December 3rd 2009, 12:28 PMfunnytim
Actually, while I'm puzzling over that problem, here's another: How do I find a definite integral?

In particular: http://www.freeimagehosting.net/uploads/f47587608f.jpg

Thanks again. - December 3rd 2009, 04:51 PMtonio