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Math Help - Easy Integral

  1. #1
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    Easy Integral

    I can't remember how to do these stupid integrals... The one im stuck on is
    x-x^2. It seems like it should be easy but im not getting anywhere.
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  2. #2
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    \int x-x^2 = \frac{x^2}{2} - \frac{x^3}{3}

    You add 1 to the exponents and then divide that term by the new raised power
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  3. #3
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    Quote Originally Posted by RockHard View Post
    \int x-x^2 = \frac{x^2}{2} - \frac{x^3}{3}

    You add 1 to the exponents and then divide that term by the new raised power
    I forgot you could split them up. Thanks.
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  4. #4
    MHF Contributor Bruno J.'s Avatar
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    Quote Originally Posted by RockHard View Post
    \int x-x^2 = \frac{x^2}{2} - \frac{x^3}{3}

    You add 1 to the exponents and then divide that term by the new raised power
    Good, but be careful with your notation! It should be \int (x-x^2)dx, not just \int x-x^2 which has no meaning. The dx is there for a reason! It might seem unnecessary when you begin calculus but later on you'll have a lot of trouble keeping up if you're not careful with notation.
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  5. #5
    MHF Contributor Drexel28's Avatar
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    Quote Originally Posted by Bruno J. View Post
    Good, but be careful with your notation! It should be \int (x-x^2)dx, not just \int x-x^2 which has no meaning. The dx is there for a reason! It might seem unnecessary when you begin calculus but later on you'll have a lot of trouble keeping up if you're not careful with notation.
    Who knows, maybe he could have been wanting to compute \int_0^1\left(x-x^2\right)d\sin(x) :O
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