find the integral of (1-x)^2 Is the answer simply (1-x)^3 / 3 ?? Not sure.. Please help
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Originally Posted by jzellt find the integral of (1-x)^2 Is the answer simply (1-x)^3 / 3 ?? Not sure.. Please help Let $\displaystyle u=1-x$ Then $\displaystyle dx = -du$ $\displaystyle -\int u^2du$ ...
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