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Thread: series

  1. #1
    Junior Member
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    series

    \sum\limits_{k=2}^{\infty} 1/(k-1)^2 + k^-2 * log k
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  2. #2
    Member
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    Nov 2009
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    Is This your series you posted, you just for the math tags.

    $\displaystyle \sum_{k=2} \frac{1}{(k-1)^2} + k^{-2} * \log{k}$

    Also you did not provide enough information for us to help you fully. The above is the summation of series terms $\displaystyle a_n$ as $\displaystyle k\to\infty$, If you want to find the sum of this series you must determine if the series converges, else wise it diverges and your limit is not finite so will not have a sum for the series as it goes to infinity
    Last edited by mr fantastic; Dec 2nd 2009 at 02:02 AM. Reason: Corrected some latex formatting
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