\sum\limits_{k=2}^{\infty} 1/(k-1)^2 + k^-2 * log k
Is This your series you posted, you just for the math tags.
$\displaystyle \sum_{k=2} \frac{1}{(k-1)^2} + k^{-2} * \log{k}$
Also you did not provide enough information for us to help you fully. The above is the summation of series terms $\displaystyle a_n$ as $\displaystyle k\to\infty$, If you want to find the sum of this series you must determine if the series converges, else wise it diverges and your limit is not finite so will not have a sum for the series as it goes to infinity