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Thread: series

  1. #1
    Junior Member
    Nov 2009


    \sum\limits_{k=2}^{\infty} 1/(k-1)^2 + k^-2 * log k
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  2. #2
    Nov 2009
    Is This your series you posted, you just for the math tags.

    \sum_{k=2} \frac{1}{(k-1)^2} + k^{-2} * \log{k}

    Also you did not provide enough information for us to help you fully. The above is the summation of series terms a_n as k\to\infty, If you want to find the sum of this series you must determine if the series converges, else wise it diverges and your limit is not finite so will not have a sum for the series as it goes to infinity
    Last edited by mr fantastic; December 2nd 2009 at 02:02 AM. Reason: Corrected some latex formatting
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