Those ratios look correct. Now, take the limit as of the absolute value of the ratios you've computed. The series converges absolutely if that limit is less than 1 and diverges if that limit is greater than 1. If the limit is 1 exactly, the ratio test is inconclusive and you will have to use some other test to determine convergence.

For the second series, for example, the limit as of the absolute value of the ratio is 3|x-1|, which is less than 1 if 2/3 < x < 4/3, equals 1 if x = 2/3 or x = 4/3, and is greater than 1 everywhere else. This tells you that the series converges absolutely if 2/3 < x < 4/3, diverges if x < 2/3 or x > 4/3, but tells you nothing of convergence if x = 2/3 or x = 4/3. That is, for these two values of x you must test for convergence using other means. When x = 2/3, you get and when x = 4/3 you get , both of which converge absolutely. So the series converges absolutely for and diverges everywhere else.