Results 1 to 2 of 2

Math Help - Need help evaluating yet another l'Hospital limit

  1. #1
    s3a
    s3a is offline
    Super Member
    Joined
    Nov 2008
    Posts
    597

    Need help evaluating yet another l'Hospital limit

    Question:

    Evaluate the limit using L'Hospital's rule if necessary

    Answer:
    1/e^(28/11)

    Can someone guide me through this one? I'm guessing ln is involved given the variable in the exponent but I can't seem to to get the right answer.

    Any help would would again be greatly appreciated!
    Thanks in advance!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor matheagle's Avatar
    Joined
    Feb 2009
    Posts
    2,763
    Thanks
    5
    Using algebra this is basic, rewrite this as

     \biggl({11x+7\over 11x}\biggr)^{-4x} =\Biggl(\biggl(1+{7\over 11x}\biggr)^{x}\Biggr)^{-4} \to (e^{7/11})^{-4} =e^{-28/11}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Calculation of a limit using L'Hospital
    Posted in the Calculus Forum
    Replies: 4
    Last Post: May 10th 2011, 08:20 AM
  2. Limit using L'hospital and maybe another trick
    Posted in the Calculus Forum
    Replies: 5
    Last Post: May 26th 2010, 07:51 AM
  3. Limit (no hospital)
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: February 2nd 2010, 12:06 AM
  4. Limit without using L'Hospital Rule
    Posted in the Differential Geometry Forum
    Replies: 4
    Last Post: November 9th 2009, 07:46 AM
  5. Limit without L'Hospital's Rule.
    Posted in the Calculus Forum
    Replies: 4
    Last Post: January 11th 2009, 02:02 PM

Search Tags


/mathhelpforum @mathhelpforum