1. ## More Partial Fraction

Somehow were given extra credit from cal II, but I am in Cal I. Can someone help me solve this problem. See attachment.

2. Originally Posted by sderosa518
Somehow were given extra credit from cal II, but I am in Cal I. Can someone help me solve this problem. See attachment.
Well, if it's for extra credit, there's not much we can do is there?

You have done the method of partial fractions, right? I saw it come up in your other threads.

Begin thus: $\frac {x - 1}{(x + 1)(x^2 + 1)} = \frac A{x + 1} + \frac {Bx + C}{x^2 + 1}$

And find A, B, and C. The A here is not to be confused with the A mentioned in your problem.