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- Nov 29th 2009, 03:22 AMozgunatalayDerivatives of exponential functions
- Nov 29th 2009, 03:33 AMe^(i*pi)
- Nov 29th 2009, 04:35 AMozgunatalay
Thank you for your solution.

- Nov 29th 2009, 04:37 AMe^(i*pi)
I suppose you could always use the quotient rule, the product rule and the chain rule but IMO that would lead to an even bigger mess

- Nov 29th 2009, 04:48 AMozgunatalay
I am learning about this new. Sometimes when I'm having difficulty solving questions. Thanks for your suggestions.

- Nov 29th 2009, 06:02 AMHallsofIvy
You might also want to note that there are NO exponential functions here. "Exponential functions" are functions that have the variable, x, in the exponent.

- Nov 29th 2009, 06:25 AMozgunatalay
I looked again and I ask questions, I reached a different result. If I've made a mistake, correct my mistakes.

http://img282.yukle.tc/images/2362turev22854.gif - Nov 29th 2009, 10:35 AMozgunatalay
Is there anyone who can check if I did it right?

- Nov 29th 2009, 10:53 AMhjortur
I can see no difference between your answer and e^(i*pi)'s, so I would conclude that this is correct.

EDIT: Ahh I see it now. e^(i*pi) did make a slight mistake in the last fraction:

is supposed to be:

- Nov 29th 2009, 11:51 AMozgunatalay
Where am I doing wrong?

- Nov 29th 2009, 11:54 AMhjortur
Nowhere. Your answer is the same as the corrected one.

- Nov 29th 2009, 12:10 PMozgunatalay
- Nov 29th 2009, 12:41 PMhjortur
Sorry (Happy), I didn't check out e^(i*pi)'s answer good enough.

But your answer is correct. - Nov 29th 2009, 01:26 PMozgunatalay
Thank you for your interest in question (Happy)(Clapping)