Very hard take home test. We're trying to figure out how to integrate:

Any help would be much appreciated. Thanks!

Printable View

- November 29th 2009, 12:09 AMDaveDammitTaylor Polynomial Problem help
Very hard take home test. We're trying to figure out how to integrate:

Any help would be much appreciated. Thanks! - November 29th 2009, 01:44 AMmr fantastic
- November 29th 2009, 02:05 AMsimplependulum
sub

the integral becomes

Since

can be changed to infinite series form .

Buy by integration by parts

Finally , the integral becomes

note that can be changed to

If

the integral

- November 29th 2009, 02:55 AMNonCommAlg
**simplependulum**, what you found is not a Taylor series. i think**DaveDammit**is probably looking for the Taylor series of at . hopefully some day he'll give us more details! - November 29th 2009, 10:18 AMDaveDammit
- November 29th 2009, 10:22 AMJameson
- November 29th 2009, 10:26 AMhjortur
You do know the definition that a third order Taylor polynomial of f(x) about a is:

.

So all you need to do is find the first 3 derivatives of f(x), and sub a=1.

Hope that helps. - November 29th 2009, 10:31 AMDaveDammit
I do know the definition of a third order Taylor polynomial. That's not the problem I'm having.

The problem I'm having is using one of the Fundemental Theorems of Calculus to integrate the function with respect to in order to find my function. This specific function is fairly challenging for me to integrate. It is a beautiful problem and I will attempt to solve it.

Thanks for your input. - November 29th 2009, 10:36 AMJameson
I didn't see NCA's note that simplependulum didn't write a Taylor polynomial so my previous post isn't correct.

I think the point of this problem is you don't need to actually integrate the function because you can use FTCII to find f(1). What is f(1) if the integral of f(t) has bounds from 1 to 1?

From there, f'(a) is just f(t) and all further derivatives can easily be found. You don't need to find the integral of f(t) to write the Taylor polynomial of f(x). - November 29th 2009, 10:46 AMhjortur

Then according to the fundamental theorem of calculus:

Do you see why?

You don't need to integrate at all.

Can you finish this one now? - December 6th 2009, 04:53 PMDaveDammit
Hey guys,

Sorry I'm so late in responding to this but I just wanted to let you guys know that I completed the problem and I think I did very well on the test. I had to calculate a wicked third derivative of the function but I'm pretty sure I got the answer right.

Thanks for all your help!

Dave