heres the problem: http://img186.imageshack.us/img186/4328/untitledil5.jpg
i marked where i'm having trouble.
I don't see how this was integrated.
can someone break it down further, for the part i marked.
thanks
[QUOTE=1-cos 2x and then that easily integrates.QUOTE]
so then using the trig identity, sinx^2 + cosx^2 = 1
1 - cos2x is the integral.
i'm going to guess what the derivative is, may need help, tried using mathematica.
hmm not sure why x is dived by 2, wheres the 1/4 coming from? .. x/2 - 1/4sin(2x) + c
thanks for all the help so far.
The half-angle identity is:so then using the trig identity, sinx^2 + cosx^2 = 1
1 - cos2x is the integral.
i'm going to guess what the derivative is, may need help, tried using mathematica.
hmm not sure why x is dived by 2, wheres the 1/4 coming from? .. x/2 - 1/4sin(2x) + c
thanks for all the help so far.
sin^2(x/2)=(1/2)(1-cos x)
cos^2(x/2)=(1/2)(1+cos x)