Assuming the result lim x approaches 0 (sinx)/(x) = 1, evalute

1) lim x approaches 0 (1-cosx)/(x)

2) lim x approaches 0 (1-cosx)(x^2)

3) lim x approaches 0 (tanx-sinx)/(x^3)

Can anyone help, I would appreciate it. My trig is horrible.

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- Nov 28th 2009, 11:07 AMsderosa518Limits
Assuming the result lim x approaches 0 (sinx)/(x) = 1, evalute

1) lim x approaches 0 (1-cosx)/(x)

2) lim x approaches 0 (1-cosx)(x^2)

3) lim x approaches 0 (tanx-sinx)/(x^3)

Can anyone help, I would appreciate it. My trig is horrible. - Nov 28th 2009, 11:27 AMadkinsjr
Remember that you can use l-hopitals rule for indeterminate forms. Have you tried that?

Here's an example, number 1 should be easy enough for you if you apply l-hopitals rule, here is the second limit:

As you can see, there isn't much trig involved in that one. It's just l-hopitals rule. - Nov 28th 2009, 11:34 AMPaperwings
You can use L'Hopital's rule. For (2) You can use the property of

to solve for the limit after doing L'Hopital's rule. - Nov 28th 2009, 12:03 PMSoroban
Hello, sderosa518!

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