# Math Help - Using a given property of an integral to evaluate and integral

1. ## Using a given property of an integral to evaluate and integral

Given:

evaluate:

Integral of just the 3 would be $3x$, and $6(\frac{1}{3})$ since $x^2dx =$ $\frac{1}{3}$ so
on $[0,1]$ the integral will be $3(1) +$ $6(\frac{1}{3})$=5? I ommited the subraction of b-a for 3x since f(0)=0.