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Thread: Using a given property of an integral to evaluate and integral

  1. #1
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    Using a given property of an integral to evaluate and integral

    Given:

    evaluate:

    Integral of just the 3 would be $\displaystyle 3x$, and $\displaystyle 6(\frac{1}{3})$ since $\displaystyle x^2dx =$ $\displaystyle \frac{1}{3}$ so
    on $\displaystyle [0,1]$ the integral will be $\displaystyle 3(1) + $$\displaystyle 6(\frac{1}{3})$=5? I ommited the subraction of b-a for 3x since f(0)=0.
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  2. #2
    Senior Member Twig's Avatar
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    Something you wonder about?

    This is correct
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