Could anyone help me with the following problems?:

a)Find the gradient of the curve:

8x^2/4x^2-3y^3 = 3y at (3,2)

b) The curve C has parametric equations x=4cos2t and y=3sint for t being between -pi/2 and pi/2.

A is the point (2,3/2) and lies on C.

The normal to C at A is 6y-16x+23. The normal at A cuts C again at point B. Find the y coordinate of point B.

Thank you so much if you can help me