Hi there,
(x-1)^99 ∂x
Also, cos^3 (ø) sin (ø) ∂ø
t*e^-t^2 ∂t
many thanks
Bryn
Hello BrynAll these integrals can be solved by substitution. The first has already been done. I'll start you off for numbers 2 & 3.
2) Put $\displaystyle \cos\phi = u$
Then $\displaystyle -\sin\phi\; d\phi=du$
So $\displaystyle \int\cos^3\phi\sin\phi\;d\phi = -\int u^3\;du=...$
3) Put $\displaystyle e^{-t^2}=u$
Then $\displaystyle e^{-t^2}(-2t)\;dt=du$
So ...?
Grandad