http://img21.imageshack.us/img21/2572/antider.jpg

im pretty sure about everything but the last one..

i guessed it but for some reason i have a good feeling about my guess.

could you please explain it to me?

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- Nov 26th 2009, 02:09 PMganurAntiderivative question
http://img21.imageshack.us/img21/2572/antider.jpg

im pretty sure about everything but the last one..

i guessed it but for some reason i have a good feeling about my guess.

could you please explain it to me? - Nov 26th 2009, 03:49 PMhjortur
The last one is correct.

But why is the first one false ? Remember is just a constant.

For the second one: if particle has constant acceleration then

And

So it is not a cubic polynomial but a square polynomial.

For the fifth one:

Let F is an antiderivative of f and G is antiderivative of g. Then (using the product rule):

And that is not fg. - Nov 26th 2009, 03:52 PMtonio
- Nov 26th 2009, 03:59 PMhjortur
hmmm, looks like we disagree on nr 6.

If F and G are antiderivatives of f then for some constant

Now since . We know that

Then it follows that , and since ,

then .

Is this not correct ? If not can you clarify Tonio ? - Nov 26th 2009, 04:13 PMtonio
- Nov 26th 2009, 04:28 PMhjortur
Thank you, I was beginning to doubt myself.(Happy)

- Nov 26th 2009, 05:16 PMganur
wow thats great help guys! really appreciate that!

though, something isnt working out for me..

for the first one, i had no idea that e is the same as c.. but okay i get it.

2. i get..

3.&4. i already had that

5. that makes sense.. yeah i didnt think of that and now im thinking that is so easy (Headbang)

6. i understand your argument, and that the answer is 'true'

so here are the answer i put in:

T, F, F, T, F, T

and it doesnt work (Wondering) - Nov 26th 2009, 07:01 PMhjortur
The trick is that nr 3 is true.

Rewrite

Then you get

And then take the derivative, remember the chain rule.

.

I am 100% sure everything other is correct.

Hope that helps.