1) Consider the solid obtained by rotating the region bounded by the given curves about the

*x*-axis.

Cut it into circles and integrate the Area.

I'm assuming the y = 0 implies to ignore the bottom of the graph. From x=2 to x=3 rotating the shape around the x axi gives a sort of funnel thing with radius

Integrate it to get the volume:

=

I integrated and I got

Which reduced to 337/12

2) Consider the solid obtained by rotating the region bounded by the given curves about the

*x*-axis.

Would the radius for this one just be the function and then repeat the process above?

yes , r = y
3) Same deal as above:

Treat the x values as boundaries for the upper half of the function and do the same thing as the first question?

yes