Let

$\displaystyle \displaystyle \int_{-4}^{3.5} f(x) dx =7, \ \int_{-4}^{-1.5} f(x) dx=10, \ \int_{1}^{3.5} f(x)dx =6.$

Find $\displaystyle \displaystyle \int_{-1.5}^{1} f(x)dx=$

and $\displaystyle \displaystyle \int_{1}^{-1.5} (7 f(x)- 10)dx= $

i found the first part to be -9 because 10+6+x=7 (solved for x)

i just cant get the second part. im just not exactly sure what it wants me to do.

thanks for any help =)