Hey guys, I love my Calc. II class and this arc length integral has me kind of stumped. I put the integral in my TI-83 calculator and got an answer but I wanted to see if any of you thought there would be a way to integrate this:

$\displaystyle \int\sqrt{1 + \frac{4}{(2x+1)^2}} dx$ on the interval $\displaystyle [\frac{1}{2},\sqrt{3} - \frac{1}{2}]$

The original problem was calculate the arc length of $\displaystyle y = \ln{2x+1}$ on the interval $\displaystyle [\frac{1}{2},\sqrt{3} - \frac{1}{2}]$

Any ideas? Try to force a perfect square trinomial in there? Thanks for any help!