So you now know that t(p)= b ln(p(1-.08)/(.08(1-p))

Set p= 0.5, t(p)= 1 : 1= b ln(.5(1- 0.8)/0.8(1-.5)) and solve for b.(c) At time t=1, fifty percent of the school population (p=0.5) has heard the rumor. What is b?

b =

Once you know b, find t(.95)= bln(.95(1-0.8)/(0.8(1- .95)).(d) At what time has ninety-five percent of the population (p = 0.95) heard the rumor?

t =

>>How exactly do I solve for the last 2 parts? How do I plug in the values?