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**mybrohshi5** The value of the limit lim n--> inf E (n above and i=1 below) pi/8n tan(ipi/24n) is equal to the area below the graph of a function f(x) on an interval [A,B]. Find f, A, and B. (Do not evaluate the limit.) for f i get tan(x) for a i get -pi/12 for b i get .1308996939 i used delta x = (b-a)/n i also used xi = a + (delta x)(i) so i know a + pi/8n = ipi/24n solved for a then (b-a)/n = pi/8n solved for b my webwork is saying its wrong???? help please. i dont know what else to do