1. Let f(x)=2x^2-4x+5

Let f(x)=2x^2 -4x+5.Suppose that F is an antiderivative of f such that
F(1)=10.Find F(x).

I think the anti derivative is as follows:

F=2∫x^2 dx -4∫x dx + 5∫1 dx
F=2.x^3/3-4.x^2/2+5.x+c

But when I plug in 1 in the F i.e F(1) ...I do not get 10 as given in the problem.Can somebody pls help me?

2. You must make c the number that makes that true. Plug in 1 for x, 10 for y then solve for c.

3. Originally Posted by Jameson
You must make c the number that makes that true. Plug in 1 for x, 10 for y then solve for c.
Yes.

So it will look like F(1)=10=2(1)^3/3 - 2(1)^2 +5(1) + c

c= (whatever you get. solve algebraically)

Rewrite F(x) with the correct value of c.