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Math Help - Solving for c

  1. #1
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    Solving for c

    How would I solve for c for the following equation,

    e^(9c/37)= 1/2(e^(36/37)-e^(18/37))
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  2. #2
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     e^{\frac{9c}{37}}= \frac{1}{2}(e^{\frac{36}{37}}-e^{\frac{18}{37}})

    Taking the natural log of both sides you get

     \frac{9c}{37}= \ln\left(\frac{1}{2}(e^{\frac{36}{37}}-e^{\frac{18}{37}})\right)

    Now divide both sides by 9 and multiply both sides by 37.
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