I'm just wondering how I find this intersection,
$\displaystyle
x=(\ln(x)^p) \quad p>1
$
where x>2
I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with.
I'm just wondering how I find this intersection,
$\displaystyle
x=(\ln(x)^p) \quad p>1
$
where x>2
I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with.