I'm just wondering how I find this intersection,

$\displaystyle

x=(\ln(x)^p) \quad p>1

$

where x>2

I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with.

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- Nov 24th 2009, 05:20 AMGuemoThe intersection of x and ln(x)^p, where p>1
I'm just wondering how I find this intersection,

$\displaystyle

x=(\ln(x)^p) \quad p>1

$

where x>2

I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with. - Nov 24th 2009, 07:58 AMDrexel28
- Nov 24th 2009, 08:06 AMGuemo
Ok, thank you, just wanted to be sure! Think I can manage from now :D