The intersection of x and ln(x)^p, where p>1

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November 24th 2009, 05:20 AM
Guemo

The intersection of x and ln(x)^p, where p>1

I'm just wondering how I find this intersection,

$<br /> x=(\ln(x)^p) \quad p>1<br />$

where x>2

I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with.
November 24th 2009, 07:58 AM
Drexel28

Quote:

Originally Posted by Guemo

I'm just wondering how I find this intersection,

$<br /> x=(\ln(x)^p) \quad p>1<br />$

where x>2

I tried to take the logarithm of both sides but I'm not sure which step to take from that, or if that's the right step to begin with.

I assume intersection (just making sure) means solve the equation $x=\ln^p(x)\quad p>1$ . There isn't a closed form solution for this.
November 24th 2009, 08:06 AM
Guemo

Ok, thank you, just wanted to be sure! Think I can manage from now :D

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