integral ( (2x^{2}-x-20) / (x^{2} + x - 6) dx

since the powers from the demon and numer are the same, i have to divide...

got it to be 2 remainder -3x-8

so:

-3x-8 / (x+3)(x-2) = A/(x+3) + B/(x-2)

=

-3x-8 = A(x-2) + B(x-3)

plugged in 2 for x: B = -11/5

plugged in -3 for x: A = -1/5

int (-1/5)/(x+3) + int (-11/5)/(x-2)

=

(-1/5)ln|(x+3)| - (11/5)ln|(x-2)| +C

i got that to be the answer, but its wrong. can someone explain what i am doing wrong?