Can anyone help me with this problem. I'm stuck, and I don't know what else to try. Thanks for any help.
The solid lies between planes perpendicular to the x-axis at x = -pi/3 and x = pi/3. The cross sections perpendicular to the x-axis are
a) circular disks with diameters running from the curve y = tanx to the curve y = sec x
b) squares whose bases run from the curve y = tan x to the curve y = sec x
This is an old question, but how would you find this analytically for part a?
For the volume, so far I have:
(pi/4) times the integral from -pi/3 to pi/3 of (2(secx)^2 - 2secxtanx - 1)dx
I tried using u-substitution, making u=secx and du=secxtanxdx, but I got stuck. Will someone help me solve this by hand? Thanks.