Results 1 to 3 of 3

Math Help - easy integration question

  1. #1
    Newbie
    Joined
    Oct 2009
    Posts
    18

    easy integration question

    sorry i am having a major brain fade..
    how do i integrate
    integrate (6sin(x))^2-3(cos(x))^2
    Last edited by mr fantastic; December 8th 2009 at 11:52 AM. Reason: rt --> de
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by calc626 View Post
    sorry i am having a major brain fade..
    how do i integrate
    integrate (6sin(x))^2-3(cos(x))^2
    \sin^2{x} = \frac{1 - \cos(2x)}{2}

    \cos^2{x} = \frac{1 + \cos(2x)}{2}
    Last edited by mr fantastic; December 8th 2009 at 11:53 AM.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,234
    Thanks
    27
     \int 6\sin^2(x)-3\cos^2(x) ~dx = \int \left(6\left(\frac{1-\cos(2x)}{2}\right)-3\left(\frac{1+\cos(2x)}{2}\right)\right) ~dx

    Does this help?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. [SOLVED] Quick easy integration question
    Posted in the Calculus Forum
    Replies: 7
    Last Post: February 2nd 2010, 08:45 AM
  2. easy log integration question
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 18th 2009, 04:38 AM
  3. Seemingly easy question... too easy.
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: August 23rd 2009, 09:36 PM
  4. Integration question that I 'should' find easy
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: May 29th 2009, 09:16 AM
  5. Easy Integration
    Posted in the Calculus Forum
    Replies: 2
    Last Post: December 9th 2007, 08:06 AM

Search Tags


/mathhelpforum @mathhelpforum