If $\displaystyle lnx^2= 3x$, Find the Value of X. I am missing a major property. Could someone help me 0ut on this one?! Thank you
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Originally Posted by r2d2 If $\displaystyle lnx^2= 3x$, Find the Value of X. I am missing a major property. Could someone help me 0ut on this one?! Thank you Do you mean $\displaystyle ln(x^2)$ or $\displaystyle [ln(x)]^2$ Either way you will need to use an iterative solution
I mean $\displaystyle ln(x^2)$
Originally Posted by r2d2 I mean $\displaystyle ln(x^2)$ There are actually no real (and possibly no complex) solutions for this equation because the two lines do not meet - see the attached graph
well I have the answer is equal to $\displaystyle e^3/2$. Or e^(3/2)
Originally Posted by r2d2 well I have the answer is equal to $\displaystyle e^3/2$. Or e^(3/2) If you sub that back into the original equation you do not get 0 $\displaystyle 2ln(e^{1.5}) \neq 3e^{1.5} $
Ok I must have copied the problem wrong. Here it is: not simplified. $\displaystyle -x-2x+2xlnx=0$ Solve for x.
Originally Posted by r2d2 Ok I must have copied the problem wrong. Here it is: not simplified. $\displaystyle -x-2x+2xlnx=0$ Solve for x. $\displaystyle -x - 2x + 2x\ln{x} = 0$ $\displaystyle -3x + 2x\ln{x} = 0$ $\displaystyle x(-3 + 2\ln{x}) = 0$ $\displaystyle x = 0$ is an invalid solution because of domain reasons. $\displaystyle \ln{x} = \frac{3}{2}$ $\displaystyle x = e^{\frac{3}{2}}$
i also got e^(3/2), you just copied it down wrong the first time, so ur correct as; -x-2x+2xlnx=0 -3x+2xlnx=0 2xlnx=3x lnx=3x/2x lnx=3/2 x=e^(3/2)
Great! Thank you everybody
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