Results 1 to 3 of 3

Math Help - Just a simple question regarding measurements

  1. #1
    Newbie
    Joined
    Nov 2009
    Posts
    14

    Just a simple question regarding measurements

    Hi guys,

    I am given a function C=a + b*T + c*T^2 +d*T^3 which is measured in [KJ/(Kg*K)]

    I am given another function h(T) = Integral(0 -> T): CdT and the measuremeant of h(T) is [KJ/Kg].

    A value Ta is given, in Celcius, so I converted it to Kelvin (Ta' = Ta+273).

    I then found the integral of h(Ta') which is: a*Ta' + (b*Ta'^2)/2 + (c*Ta'^3)/3 + (d*Ta'^4)/4

    Is the answer I found in [KJ/Kg] or [KJ/(Kg*K)] ?

    If it's the latter, how do I make it in [KJ/Kg] ?

    Regards
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,621
    Thanks
    426
    Quote Originally Posted by meddi83 View Post
    Hi guys,

    I am given a function C=a + b*T + c*T^2 +d*T^3 which is measured in [KJ/(Kg*K)]

    I am given another function h(T) = Integral(0 -> T): CdT and the measuremeant of h(T) is [KJ/Kg].

    A value Ta is given, in Celcius, so I converted it to Kelvin (Ta' = Ta+273).

    I then found the integral of h(Ta') which is: a*Ta' + (b*Ta'^2)/2 + (c*Ta'^3)/3 + (d*Ta'^4)/4

    Is the answer I found in [KJ/Kg] or [KJ/(Kg*K)] ?

    If it's the latter, how do I make it in [KJ/Kg] ?

    Regards
    dT is in degrees K ...

    \int_0^T C(T) \, dT = \frac{kJ}{kg \cdot K} \cdot K = \frac{kJ}{kg}
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2009
    Posts
    14
    Thank you mate :-)

    By the way is this the right sub-forum to ask questions regarding Bisection/Newton-Raphson/Single-point root-estimating methods ?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. LOgic Question 0n Measurements
    Posted in the Math Puzzles Forum
    Replies: 2
    Last Post: August 9th 2011, 06:10 PM
  2. Easy Question - Simple Interest, Simple Discount
    Posted in the Business Math Forum
    Replies: 0
    Last Post: September 21st 2010, 08:22 PM
  3. Replies: 4
    Last Post: May 4th 2010, 09:08 AM
  4. measurements
    Posted in the Geometry Forum
    Replies: 1
    Last Post: October 20th 2009, 07:19 PM
  5. Measurements
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 29th 2009, 10:48 PM

Search Tags


/mathhelpforum @mathhelpforum