I am given a function C=a + b*T + c*T^2 +d*T^3 which is measured in [KJ/(Kg*K)]
I am given another function h(T) = Integral(0 -> T): CdT and the measuremeant of h(T) is [KJ/Kg].
A value Ta is given, in Celcius, so I converted it to Kelvin (Ta' = Ta+273).
I then found the integral of h(Ta') which is: a*Ta' + (b*Ta'^2)/2 + (c*Ta'^3)/3 + (d*Ta'^4)/4
Is the answer I found in [KJ/Kg] or [KJ/(Kg*K)] ?
If it's the latter, how do I make it in [KJ/Kg] ?