rotational volume question

Hi all, here's my question:

Find the volume of the solid formed by rotating the region enclosed by

y=e^(2x) + 1, y=0, x=0, x=0.2

about the y-axis.

My attempt at a solution:

V = pi int{ x = 0 to 0.2} [ (e^(2x) + 1)^2 dx]

V= pi int{ x = 0 to 0.2} [ ( e^(4x) + 2 e^(2x) + 1) dx]

V= pi { x = 0 to 0.2} ( (1/4) e^(4x) + (2/2) e^(2x) + x)

V = pi ( [(1/4) e^(0.8) + e^(0.4) + 0.4] - [(1/4) + 1] )

This isn't the right answer though. I'd like to know what I did wrong so I can get credit here and do problems right in the future. Thanks!!!!!