Can anyone explain the procedures in solving these two problems using L'Hospital's rule? 1. lim x-> 0+ (tan 2x)^x 2. lim x-> 1 (2 - x)^tan((pi)x/2)
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If the function is of indeterminate form, then take the derivative and find the limit of that. Read up, a tad on L'Hop's rule, it is not a hard rule you just need to know when to apply it
Hello, Eternal! Here's the second one . . . Let: . Take logs: . Apply L'Hopital: . Take limits: . We have: . Therefore: .
Hello again, Eternal! It took a while to get the first one. I hope I'm right . . . As given, the limit goes to . . . an indeterminate form. Let: . Take logs: . Apply L'Hopital: . Apply L'Hopital: . Take the limit: . We have: . , . . therefore: .
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