Here is the sample problem (but the object will change for the test):

Optimization.The base b and height h of an isosceles triangle vary in such
a way that its perimeter,is constant,and equal to 6. Find the maximum possible area of the triangle.

What I know from this:
P=B * 2S (base times the 2 sides)
P=6
A=BH (base times height)

From the question I also think that I will be needing to find f' and f'' to find the maximimum area for the triangle, but I am not sure on that.

I always get confused on the steps to work through optimization word problems. Can someone please help? I understand more if there is a step by step process to solve something.

2. Originally Posted by operaphantom2003
What I know from this:
P=B * 2S (base times the 2 sides) <--?
...
A=BH (base times height) <--?
As a start, try this:
Perimeter = b + s + s = 6
Area = $\displaystyle \dfrac{b \cdot h}{2}$

s = $\displaystyle \sqrt{ h^2 + \left(\dfrac{b}{2} \right)^2 }$
I also think that I will be needing to find f'
You are thinking right.
.