I need help solving: integral of (20x-30) / (x(x-2)(x^2-2x+5)) If I try to decompose it; I will have LHS from above = (A/x)+(B/x-2) + ? Stuck here.
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You can use the third factor: C will a function of x.
ohh I see, but I didnt think the polynomial could be there under Cx+D because its not factored? So, now I am suppose to multiply both sides by (x(x-2)(x^2-2x+5))?
Originally Posted by shadow85 ohh I see, but I didnt think the polynomial could be there under Cx+D because its not factored? So, now I am suppose to multiply both sides by (x(x-2)(x^2-2x+5))? Yes and find the values of A,B,C and D substitute and evaluate the resulting integrals.
If we let and we know The original fraction can be expressed in the form of : we can see the last term the numerator is a polynomial with degree , that means we do not need to break it down into pieces anymore . If we continue , we can obtain
umm wasnt the second post, enough to solve this?
Not quite, because you to solve you would have to have a polynomial in the third fraction. I did say that C was a polynomial, but I didn't say of what order.
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