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Math Help - Integral Problems

  1. #1
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    Integral Problems

    uo
    Last edited by coolio; February 28th 2007 at 06:11 PM.
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  2. #2
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    I am not going to do the definite integral, rather I will find the anti-derivative and leave you to evaluate them at the endpoints.
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  4. #4
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    Quote Originally Posted by ThePerfectHacker View Post
    I am not going to do the definite integral, rather I will find the anti-derivative and leave you to evaluate them at the endpoints.
    Can explain, perfecthacker, in your math ways, why if u = x, then du = 1 ?
    Never have I encountered that before in my math ways?

    Do you have your own math ways?
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  5. #5
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    Quote Originally Posted by ThePerfectHacker View Post
    I am not going to do the definite integral, rather I will find the anti-derivative and leave you to evaluate them at the endpoints.
    Again, if u' = 1
    Then u = x --------------???

    Also, if v = arcsin(x)
    Then v' = 1 / sqrt(1 -x^2) ------------???

    then INT. [u]dv
    = INT. [x / sqrt(1-x^2)]dx ---------where did you get dx?
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  6. #6
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    Quote Originally Posted by ticbol View Post
    Can explain, perfecthacker, in your math ways, why if u = x, then du = 1 ?
    Never have I encountered that before in my math ways?

    Do you have your own math ways?
    In my other post in geometry, I talk about "rigorous" and how important it is to mathemations.

    Now, the concepts of differenencials, splitting the dy and the dx as if they are fractions.

    Like for example,
    dy/dx=y
    Then,
    (1/y)dy=dx
    Is not really acceptable among mathemations because they are not fractions. Thus, I use a more formal approach which does not involve splitting the denominator of the differencial.

    I wrote a Calculus thread over here.
    http://www.mathhelpforum.com/math-he...utorial-2.html

    (The math program that is used to generate math code is math working properly now, thus you might not see everything).

    In that thread I explain how I do integration via the substitution rule my way.

    ~~
    And yes, that is my own techinque.
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