Solved!
Last edited by r2d2; Nov 19th 2009 at 01:02 PM.
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f '(a) = lim [f(a+h)-f(a)]/h For yur problem note: ln[(3+h)/3] = ln(3+h) - ln(3) you have lim [ln(3+h) - ln(3)]/h What are f(x) and a?
Oh Right! Properties of the natural log : dividing turns into subtracting. 'a' would be equal to 3 and the function be ln(x)? Then would I solve the derivative of ln(x) to get l/x, then plug in 3 for x?
you got it
So when it says find the derivative, then answer would be 1/3. I just had to recognize the fact the I could change the ln function into the definition of a derivative. Thank you Sir!
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