This is a question about the function f(x) = 1 + e–2x.
First I have to find f¢(x). I have found this to be: -2e^-2x
Then I have to:
Let P be the point on the graph of f where x = –1/2.
(b) Find an expression in terms of e for
(i) the y-coordinate of P;
(ii) the gradient of the tangent to the curve at P.
and finally I have to
(c) Find the equation of the tangent to the curve at P, giving the answer in the form y = ax + b.
I would appreciate your help.