I am confused how to integrate the equation below the result
should be /6 ???
$\displaystyle \int\limits_{0}^{1}\frac{1}{\sqrt{4-x^2}}\, dx$
Thank you in advance!
I am confused how to integrate the equation below the result
should be /6 ???
$\displaystyle \int\limits_{0}^{1}\frac{1}{\sqrt{4-x^2}}\, dx$
Thank you in advance!