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Math Help - calculate water depth rate..

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    Question calculate water depth rate..

    The depth of water,y in feet of water in Boston harbor is given in terms of t the number of hours since midnight by y=5+4.9cos(πt/6).Calculate the water depth at 2:00pm and also calculate the rate at which the water depth is changing at that time.
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    Quote Originally Posted by mathcalculushelp View Post
    The depth of water,y in feet of water in Boston harbor is given in terms of t the number of hours since midnight by y=5+4.9cos(πt/6).Calculate the water depth at 2:00pm and also calculate the rate at which the water depth is changing at that time.
    For depth of H2O (water) put t=14. As far as the rate is concerned differentiate with respect to t. dy/dt =0 -4.9sin(nt/6)(n/6) First you take derivative of cos then you take the derivative of nt/6. n=pi
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