Thread: calculate water depth rate..

The depth of water,y in feet of water in Boston harbor is given in terms of t the number of hours since midnight by y=5+4.9cos(πt/6).Calculate the water depth at 2:00pm and also calculate the rate at which the water depth is changing at that time.

Originally Posted by mathcalculushelp

The depth of water,y in feet of water in Boston harbor is given in terms of t the number of hours since midnight by y=5+4.9cos(πt/6).Calculate the water depth at 2:00pm and also calculate the rate at which the water depth is changing at that time.

For depth of H2O (water) put t=14. As far as the rate is concerned differentiate with respect to t. dy/dt =0 -4.9sin(nt/6)(n/6) First you take derivative of cos then you take the derivative of nt/6. n=pi