If f(x) = ∫4x^3 (x^3 on top, 4 on bottom) t^5 , find f'(x) find f'(4)
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Originally Posted by derekjonathon If f(x) = ∫4x^3 (x^3 on top, 4 on bottom) t^5 , find f'(x) find f'(4) You'll need to apply the FTC part 1: $\displaystyle \frac{\,d}{\,dx}\left[\int_{a}^{g(x)}f\!\left(t\right)\,dt\right]=f\!\left(g\!\left(x\right)\right)\cdot g^{\prime}\!\left(x\right)$. Can you take it from here?
How the g(x) relates to the t^5dt part..... how do I show a function of x^3 when I don't even see the variable (x) in the part that says t^5dt?
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It seems like it should be simple, but I'm just not getting it. How do I find f'(x)?
Originally Posted by derekjonathon It seems like it should be simple, but I'm just not getting it. How do I find f'(x)? You will need to post the integral in your question more clearly - it's clear that what we think it is is different to what you think it is.
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