$\displaystyle \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx} $ find this ratio!
Last edited by mathkeep; Nov 19th 2009 at 06:05 AM.
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Originally Posted by mathkeep $\displaystyle \frac{\int_0^pi{x^3log(sinx)}{\int_0^pi{x^2log(\sq rt{2}sinx)dx}$ find this ratio! Did you mean: $\displaystyle \int_0^{\pi}x^2log(\sqrt{2} sin x)dx$ ?
Originally Posted by mathkeep $\displaystyle \frac{\int_0^pi{x^3log(sinx)}{\int_0^pi{x^2log(\sq rt{2}sinx)dx}$ find this ratio! Or for those that can't read LaTeX Error (I think) $\displaystyle \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx} $
Originally Posted by Danny Or for those that can't read LaTeX Error (I think) $\displaystyle \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx} $ hey thanks Danny..thats right..i wanted to write that. thank you.
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