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Math Help - find the ratio

  1. #1
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    find the ratio

    \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx}
    find this ratio!
    Last edited by mathkeep; November 19th 2009 at 06:05 AM.
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  2. #2
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    Quote Originally Posted by mathkeep View Post
    \frac{\int_0^pi{x^3log(sinx)}{\int_0^pi{x^2log(\sq  rt{2}sinx)dx}
    find this ratio!
    Did you mean:

    \int_0^{\pi}x^2log(\sqrt{2} sin x)dx

    ?
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  3. #3
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    Quote Originally Posted by mathkeep View Post
    \frac{\int_0^pi{x^3log(sinx)}{\int_0^pi{x^2log(\sq  rt{2}sinx)dx}
    find this ratio!
    Or for those that can't read LaTeX Error (I think)

    \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx}
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  4. #4
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    Quote Originally Posted by Danny View Post
    Or for those that can't read LaTeX Error (I think)

    \frac{\int_0^{\pi} x^3log(sinx)}{ \int_0^{\pi} x^2log(\sqrt{2}sinx)dx}
    hey thanks Danny..thats right..i wanted to write that.
    thank you.
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