[SOLVED] The difference of the harmonic series and 1/n comparsion

I recently had this classic example to determine if it converged or diverged

[MATH\frac{sin(n)}{n}][/tex]

I learned that you can use a comparison test using the squeeze theorem.

$\displaystyle \frac{-1}{n}\le\frac{sin(n)}{n}\le\frac{1}{n}$

Then you would take the limit of

$\displaystyle \lim_{n\to\infty}\frac{1}{n}$ which was go to 0.

Because the function was greater than the original you can say the original converged as well to a limit of 0.

However, how would the harmonic series, diverge if you are basically determining the limit of the same thing

**Edit: Poor question, trying to mark as solved, please disregard, if misused the concept of series and sequence**