Proving a function is continuous

it is continuous because f(0) = 0. However, I'm not clear how to find such delta. We have to find a positive delta such that |f(x) - f(0)| < epsilon = |x sin(x) | < epsilon when |x sin x| < delta.

How to find such delta? Does delta = epsilon? I'm not clear

This should be of some help.

http://www.mathhelpforum.com/math-he...ta-proofs.html

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Originally Posted by xyz

http://i291.photobucket.com/albums/l...Capture887.jpg

Ofcourse it is continuous because f(0) = 0. However, I'm not clear how to find such delta. We have to find a positive delta such that |f(x) - f(0)| < epsilon = |x sin(x) | < epsilon when |x sin x| < delta.

How to find such delta? Does delta = epsilon? I'm not clear

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Prove: .

Hint: