anyone can help me how to differentiate x^x and 2^x?
If you show me the working and explanation for each steps
it would be great..! THanks!
for $\displaystyle a > 0$ , $\displaystyle \frac{d}{dx}(a^x) = a^x \cdot \ln{a}$
you'll need to use logarithmic differentiation to find the derivative of $\displaystyle y = x^x$
http://http://tutorial.math.lamar.ed...I/LogDiff.aspx
see example 2.