# Thread: Limit graph with decimals

1. ## Limit graph with decimals

I think that this problems is sorry to say the least. I wants me to take the right and left hand limits, but to my observation the coordinating values are decimals.

Below is the graph and here it asks me, also I have the answers only to those without a question mark

1. The limit as x approaches 0.8 from the left hand side:?
2. f(0.8)=0.8
3. The limit as x approaches 0.8 from the right hand side:?
4. Is this function continuous at 0.8 (Y/N): No

2. Originally Posted by qbkr21
I think that this problems is sorry to say the least. I wants me to take the right and left hand limits, but to my observation the coordinating values are decimals.

Below is the graph and here it asks me, also I have the answers only to those without a question mark

1. The limit as x approaches 0.8 from the left hand side:?
2. f(0.8)=0.8
3. The limit as x approaches 0.8 from the right hand side:?
4. Is this function continuous at 0.8 (Y/N): No

How can f(0.8) = 0.8? The value of f at this point is clearly 0. (That's what the red dot is telling you.)

From the left, I get that lim f(0.8) is about -0.6 and from the right I get that lim f(0.8) is about -1.1. Since these limits are not the same, the function is not continuous at this point.

-Dan

1. -0.6
3. -1.2

I can't stand math teachers who make up problems like this. They should just die. Counting every hash mark in multiples of 2 is why I hate doing there homework. If they have nothing else do do besides create homework like this they should quit teaching. Ludicrous!

4. Originally Posted by qbkr21

1. -0.6
3. -1.2

I can't stand math teachers who make up problems like this. They should just die. Counting every hash mark in multiples of 2 is why I hate doing there homework. If they have nothing else do do besides create homework like this they should quit teaching. Ludicrous!
On the other hand, when doing a physical experiment you have to be able to read the graph so some experience doing so in school is a good idea. (That you and I got slightly different answers is one of the reasons the concept of statistical error was developed.)

-Dan