Can anyone show me how the limit of $\displaystyle \frac{sin 5x}{x}$ as x goes to 0 equals 5? I'm only supposed to use the fact that $\displaystyle \frac{sin x}{x}$ goes to 1 as x goes to 0. Any tips?
Follow Math Help Forum on Facebook and Google+
Originally Posted by paupsers Can anyone show me how the limit of $\displaystyle \frac{sin 5x}{x}$ as x goes to 0 equals 5? I'm only supposed to use the fact that $\displaystyle \frac{sin x}{x}$ goes to 1 as x goes to 0. Any tips? If we let $\displaystyle z=5x$ then our limit becomes $\displaystyle \lim_{z\to0}\frac{\sin(z)}{\tfrac{z}{5}}$........so
View Tag Cloud