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Math Help - Simple Calculus

  1. #1
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    Simple Calculus

    My math class has just started getting into calculus and I have a few questions that I'd like to ask. Our school uses a program called TLM that spits out some random math problems from a huge database, and here are a couple of questions that I'm having trouble with.

    Given the function f(x) = 4x^2-1x+4
    evaluate f(2+\Delta x)

    For this question should I just pop in 2+\Delta x for x?

    EDIT:

     y=5x^2+6x+21

    The question then asks me what is \Delta Y and \Delta y / \Delta x when x changes from 1.6 to 2.2
    For delta y I just subbed in the numbers and got 15

    For finding the dy/dx I'm drawing a complete blank. I feel like it should be easy but I can't figure out what to do.
    Last edited by Crell; November 16th 2009 at 01:01 PM.
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  2. #2
    Senior Member
    Joined
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    You are correct for the first question:

    f(2+\Delta x)=4(2+\Delta x)^2-(2+\Delta x)+4.

    Your answer to the second question also looks correct. To find \frac{\Delta y}{\Delta x}, we just divide the answer by \Delta x=2.2-1.6.

    To find \frac{dy}{dx}, we evaluate what is called a limit:

    \frac{dy}{dx}=\lim_{\small \Delta x\rightarrow 0}\frac{f(x+\Delta x)-f(x)}{\Delta x}.

    We can do this by simplifying the fraction and noting that certain terms containing \Delta x approach 0 as \Delta x itself approaches zero, leaving us with the derivative of the function f(x).

    Hope this helps!
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  3. #3
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    Thanks for the answers Scott, but I'm still having a bit of trouble grasping the concept for the second part of my second question.


     y=5x^2+6x+21 when x changes from 1.6 to 2.2.

    Find \frac {\Delta y} {\Delta x}

    I don't really understand what "rule" or equation to use to find the answer. It ended up being 25.

    Again, any help is much appreciated!

    EDIT: I found out this is the delta process, but I'm still attempting to wrap my head around it.
    Last edited by Crell; November 17th 2009 at 04:40 PM.
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