# Math Help - Another chain rule problem

1. ## Another chain rule problem

Here it is:

"Given y=f(x) with f(1)=4 and f'(1)=3, find

(a) g'(1) if g(x)=sqrt(f(x))
(b) h'(1) if h(x)=f(sqrt(x))"

I've figured out (a), and the answer is 3/4. But I can't get (b).
How do you solve it and what's the difference between the two annotations?

2. $h'(x)=\frac{f'(\sqrt{x} )}{2\sqrt{x} }$

3. Originally Posted by Jose27
$h'(x)=\frac{f'(\sqrt{x} )}{2\sqrt{x} }$
But what would $f'(\sqrt{x})$ be?
4. I don't know exactly, but you're only asked to evaluate $h'(1)$ and since $\sqrt{1} =1$ and you know the value of $f'(1)$...
$h'(1) = \frac{f'(1)}{2\sqrt{1}} = \frac{3}{2}$