Thread: Differential equations, need help with further simplifying

I have tried and tried to figure this out, please help.

Find the general solution to this problem:
2x(y+1) - y dy/dx = 0
This is how far I've gotten:
2x(y+1)= ydy/dx
2x(y+1)dx = ydy
2xdx = y/(y+1) dy
∫2xdx = ∫ y/(y+1) dy
x^2 + C = ∫ y/(y+1) dy
Then I get stuck. How do I finish this?

Originally Posted by wmw88

I have tried and tried to figure this out, please help.

Find the general solution to this problem:
2x(y+1) - y dy/dx = 0
This is how far I've gotten:
2x(y+1)= ydy/dx
2x(y+1)dx = ydy
2xdx = y/(y+1) dy
∫2xdx = ∫ y/(y+1) dy
x^2 + C = ∫ y/(y+1) dy
Then I get stuck. How do I finish this?